Can anybody show me how to do this? 4 times the square root of (4-x) = square root of (5x+1)
Square both sides of the equation. It becomes a lot easier.
ok thank you Rudy :)
but how do i square it with the 4 in front...do i just ignore it?
Nope. Square it too. It comes out as: \[4^2(4-x)^2=(5x+1)^2\]
sorry, missed the square root on the previous post. So actually. 16(4-x)=5x+1 Is the actual answer. Just do the multiplication and solve for x.
ok i was wondering about the 16 haha but that helps thank you
ok i got 63= 21x which will come out as 3 ...did I do all that right?
A quick check, is just to sub 3 into the original equation wherever you have an x. When you do that it comes out as 4=4, which is valid. Your solution is correct!
yay! thanks again
you're welcome.
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