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Mathematics 6 Online
OpenStudy (anonymous):

Can anybody show me how to do this? 4 times the square root of (4-x) = square root of (5x+1)

OpenStudy (anonymous):

Square both sides of the equation. It becomes a lot easier.

OpenStudy (anonymous):

ok thank you Rudy :)

OpenStudy (anonymous):

but how do i square it with the 4 in front...do i just ignore it?

OpenStudy (anonymous):

Nope. Square it too. It comes out as: \[4^2(4-x)^2=(5x+1)^2\]

OpenStudy (anonymous):

sorry, missed the square root on the previous post. So actually. 16(4-x)=5x+1 Is the actual answer. Just do the multiplication and solve for x.

OpenStudy (anonymous):

ok i was wondering about the 16 haha but that helps thank you

OpenStudy (anonymous):

ok i got 63= 21x which will come out as 3 ...did I do all that right?

OpenStudy (anonymous):

A quick check, is just to sub 3 into the original equation wherever you have an x. When you do that it comes out as 4=4, which is valid. Your solution is correct!

OpenStudy (anonymous):

yay! thanks again

OpenStudy (anonymous):

you're welcome.

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