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OpenStudy (anonymous):
Help!?!?!?!?
5. For the function g(x) = 14/x + 3 , find (g^–1∘ g)(4). (1 point)
6
10
4
0
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OpenStudy (anonymous):
5. For the function g(x) = 14/x + 3, find (g–1∘ g)(4). (1 point)
6
10
4
0
OpenStudy (anonymous):
@jim_thompson5910
jimthompson5910 (jim_thompson5910):
g(x) is
\[\Large g(x) = \frac{14}{x}+3\]
OR
\[\Large g(x) = \frac{14}{x+3}\]
??
OpenStudy (anonymous):
The second one :)
jimthompson5910 (jim_thompson5910):
first find the inverse
\[\Large g(x) = \frac{14}{x+3}\]
\[\Large y = \frac{14}{x+3}\]
\[\Large x = \frac{14}{y+3}\]
\[\Large x(y+3) = 14\]
\[\Large xy+3x = 14\]
\[\Large xy = 14-3x\]
\[\Large y = \frac{14-3x}{x}\]
\[\Large g^{-1}(x) = \frac{14-3x}{x}\]
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jimthompson5910 (jim_thompson5910):
Now plug x = 4 into g(x). Tell me what you get.
OpenStudy (anonymous):
g^-1(4) = 2/4 or 0.5
jimthompson5910 (jim_thompson5910):
no g(x) first
jimthompson5910 (jim_thompson5910):
\[\Large g(x) = \frac{14}{x+3}\]
\[\Large g(4) = \frac{14}{4+3}\]
\[\Large g(4) = ?\]
OpenStudy (anonymous):
2
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jimthompson5910 (jim_thompson5910):
then plug that result into the inverse
OpenStudy (anonymous):
Sorry, is the inverse the original equation?
jimthompson5910 (jim_thompson5910):
no, the original is the original
i showed you how to find the inverse above
OpenStudy (anonymous):
Right! g^-1(2) = 4
jimthompson5910 (jim_thompson5910):
yep
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OpenStudy (anonymous):
Ok cool!! Thanks for the help!!! :)
jimthompson5910 (jim_thompson5910):
yw
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