Question

Y^2-5y+4

Answer 1

Assuming Y=y, I see a 2nd degree polynomial in y. You're not asking a question, so I will just calculate some fun stuff associated with it...

Factorize: (y-1)(y-4).
Zeroes: (y-1)(y-4)=0, so y=1 or y=4.
If f(y)=y^2-5y+4, then the graph of f is a parabola.
There is a vertex when y is the mean of the zeroes: y=2.5.
The value is f(2.5) = -2.25.
The axis of symmetry of the parabola is x = 2.5.
The derivative of f is f'(x)=2y-5.

Maybe there is something of value for you in this all.
You also could consider asking a question ;)

Answer 2

@ZeHanz so the answer is... (y-1)(y-4)?

Answer 3

@Harkirat can you help me/

Answer 4

are you trying to figure out how to factorize?

Answer 5

@DanL33 how to do this problem.

Answer 6

i am doing a study sheet that i can use on a test that starts in 15 minutes. and i need tto learn how to solve this problem

Answer 7

Yes but you can't just solve a problem... You first need to know if you need to factor it. Find the zeros etc..

Answer 8

okkk, does this problem need to be factorized?

Answer 9

\[Y^2-5y+4\]

because it is Y^2 we know it must factor down into

(Y plus or minus something) (Y plus or minus something)

because it is a negative followed by a positive we know that they are both

(Y - something) (Y - something)

(if you need explanation just ask)

we are now looking for numbers that multiply to make 4 and add together to make 5

1x4 = 4
1+4 = 5
2x2 = 4
2+2 = 4
so it must be 1 and 4

(Y - 1) (Y - 4)

Answer 10

ok... i can work with that

Answer 11

@DanL33 is correct

Answer 12

so (y-1)(y-4) is the answer?

Answer 13

correct

Answer 14

jst factorize