Question

Check my work in stochiochemistry. Did I get the correct result?

Answer 1

@dpaInc @jhonyy9 @Outkast3r09

Answer 2

2 C8H18 + 25 O2 = 16 CO2 + 18 H2O
the ratio between C8H18 and CO2 is 2 : 16
moles CO2 formed = 3.5 x 16/ 2= 28

Answer 3

Oh right! I did that before I corrected the equation.

Answer 4

:) did that help?

Answer 5

Yeah, I have a couple more. If you could check them as well, that would be great.

Answer 6

okay tag me when you post

Answer 7

It functions based on the original equation.

Answer 8

@sara1234

Answer 9

We shall assume that C8H18 is in excess. First calculate the moles of O2:

n(O2) = 300 g / 32.00 g/mol = 9.375 mol

Determine the moles H2O using the mole ratio; 18 moles of H2O are formed when 25 moles of O2 react.

n(H2O) = (9.375 mol O2)(18 mol H2O / 25 mol O2) = 6.75 mol H2O

Multiply the moles of H2O by Avogarod's number to determine # of molecules:

(6.75 mol)(6.01x10^23 molecules/mol) = 4.1x10^24 molecules

Answer 10

Last one. Thanks @sara1234 !

Answer 11

@AccessDenied Could you check this for me?

Answer 12

@aaronq @kelly226

Answer 13

Could you help me with this last problem? I already did it, but it would be great if you could check it. It's a23.png, and the equation is at the top.

Answer 14

Well, the top as in the top image.

Answer 15

@ghazi @kymber

Answer 16

well 2 moles of C8H18 yeilds 16 moles of CO2
1 mole of C8H18 will yeild 8 moles of CO2
therefore 3.5 moles of C8H18 will yeild 8*3.5=28 moles of CO2