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OpenStudy (anonymous):
how many molecules of carbon dioxide gas are present in 28.0 grams of co2?
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OpenStudy (aaronq):
moles=mass/molar mass 1 mole = 6.023x10^23 all the info you need to solve this problem is here, go
OpenStudy (anonymous):
do you just divide the 28 grams by 6.022x10^23?
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