Question

Write the expression as a single logarithm with a coefficient of 1.

ln3-2ln4+ln32

I know the correct answer, I just need help with the steps needed to arrive at the answer. Thanks in advance.

Answer 1

a*ln(x) = ln(x^a)
ln(x)-ln(y)= ln(x/y)
ln(x)+ln(y)= ln(x*y)

Answer 2

On your calculator do the following:

ln(2)+ln(3) and see if it equals ln(6)

ln(6)-ln(2) should then also be equal to ln(3)

What can you figure out from this?

Answer 3

Kainui, ln 2+ ln 3= Ln (2)(3), and Ln 6-Ln2= Ln (6/2)

Is that right? I'm not sure why this problem is confusing me so much, I've done many others similar to this one with no trouble.

Thanks for the help, hopefully I can figure it out.

Answer 4

Also, you're correct, but...

2ln4=ln(4^2)=ln(16)

Maybe that's where you're going wrong?

Answer 5

No, I got that, I think I'm just getting mixed up on my properties of logarithms. However, I just figured it out, and realized I was actually doing the problem correctly, I was just entering it into my calculator wrong. Whoops.

Thanks for your help.

Answer 6

Cool.