Question

Say I have a row vector in Matlab called C

Answer 1

I need to add all the 1's together, so 512+256+128+64+16+8+4+2

Answer 2

Do you have a 2x12 matrix with both of these data? Or are they separate vectors?

Answer 3

It's just a seperate matrix 12 x 1

Answer 4

only binary values.

Answer 5

Use a for loop to go through each binary number in your vector C.

Then convert it to decimal and add it to a total sum.

Give me a sec and I'll try it out and share the code

Answer 6

Alright

Answer 7

there is no decimal places in the binary number right?

Answer 8

no

Answer 9

Just 1s and 0s if that's what you mean.

Answer 10

Also, it turns out the Vector is a column vector, not row

Answer 11

so 1 x 12

Answer 12

cool. now do you know how to convert binary to decimal?

It's just:

given a1, a2, a3, a4 (the numbers that make up a binary number)

It's decimal equivalent is: (a1)(2^3) + (a2)(2^2) + (a3)(2^2)

Answer 13

it's easy to convert between row and collumn vectors with transpose()

Answer 14

Can I use the function v = bi2de(b); where b is the vector?

Answer 15

haha, didn't even know that existed. And yes you can I just tried it and it certainly works.

..and I almost had it too:(

Answer 16

but you have to use transpose() first to convert it into a row vector

Answer 17

This appears to work. Try it yourself. It gives me 990 as the total

clc; clear all;

a=[0 0 1 1 1 1 0 1 1 1 1 0];
b=[2048 1024 512 256 128 64 32 16 8 4 2 1];
ttl=0;

for n=1:12
if(bi2de(a(n)))==1
ttl=ttl+b(n)
end
end

Answer 18

hmm, I guess you need that because it doesn't seem to work when you have leading zeroes oddly

Answer 19

Just use this:

function [accum] = binaryConverter(C)

accum = 0;

for i = 1:(length(C))
decimalPlace = length(C) - i;

accum = accum + C(i)*2.^(decimalPlace);
end
end

Answer 20

Because matlab indices start from left to right but you need to count decimal places from right to left. That is why there is separate i and decimalPlace variables

Answer 21

you can also use fliplr()
It flips a vector left to right at once.

Answer 22

cool, that will surely come in handy.

But using that here you still end up have one variable counting the opposite way of the other

Answer 23

Is function an invalid variable?

Answer 24

if you're incorporating this into something else just use:

accum = 0;

for i = 1:(length(C))
decimalPlace = length(C) - i;

accum = accum + C(i)*2.^(decimalPlace);
end

since in matlab .m files can be either functions or scripts

Answer 25

using this you're assuming C has already been made and accum is your result.

This method removes the need for that extra vector of powers of 2.

Answer 26

So, v is the vector that has these binary numbers

Answer 27

is that what is it supposed to be?

Ifso, given v = [0, 0, 1, 1, 1....]

accum = 0;

for i = 1:(length(v))
decimalPlace = length(v) - i;

accum = accum + v(i)*2.^(decimalPlace);
end

and accum will be your answer(a 1x1 scalar matrix) (Since everything in matlab is a matrix)

Answer 28

ok, It work perfectly.

Answer 29

congrats, matlab rocks, also EE ftw!

Answer 30

Thanks!!!