Question

Given that f(x)=x^3 find all values of x in the interval (-1, 1) that satisfy the mean value theorem.

Answer 1

is this really how the question reads?

Answer 2

points don't "satisfy the mean value theorem" a function does

Answer 3

in any case we can compute \(\frac{f(1)-f(-1)}{1+1}=\frac{2}{2}=1\) and solve
\[f'(x)=3x^2=1\] for \(x\)

Answer 4

divide by 3, take the square root, don't forget the \(\pm\)

Answer 5

Thank you.