Question

How do you find the G(40) of this equation? G(x)=log sub3 (2x+1)-2 ?

Answer 1

well this is how the problem was solved i'm just trying to figure out what happend to the log3 and the (81) towards the end.
G(40)= log sub3(2(40)+1)-2
= log sub3 (81)-2
G(40)= 2

Answer 2

\(\large G(40)=log_3(2\cdot 40+1)-2 \)
\(\large G(40)=log_3(80+1)-2 \)
\(\large G(40)=log_3(81)-2 \)
now,
\(\large log_3(81)=m \Leftrightarrow 3^m=81 \)
this means m=4 so
\(\large G(40)=4-2=2 \) .....:)

Answer 3

thank you