Question

What are the FOCI of the following graph?

Answer 1

no the answer is D
do you wana know why?

Answer 2

you got the 3 and the 5 right?

Answer 3

lets do them one at a time
@binary3i is responding to the first one i will take the second

Answer 4

fine.
b was the vertex
but focus is the point
from where the distance to any point on curve will also be equal to the distance betwen te point on curve and directrix.
ab=bp

Answer 5

yo @charlotteakina

Answer 6

the vertices are \((0,4)\) and \((0,-4)\) so you know the \(y^2\) term comes first, and it looks like
\[\frac{y^2}{16}-\frac{x^2}{b^2}=1\] you need \(b^2\)
the focus is at \((5,0)\) tells you \(5^2=16+b^2\) and so \(b^2=25-16=9\)
your equation is
\[\frac{y^2}{16}-\frac{x^2}{9}=1\]

Answer 7

ok