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Help with finding volume? What volume of 1.25 M sodium hydroxide (NaOH) solution can be prepared using 60.0 g of sodium hydroxide? (The mass of one mole of NaOH is 40.0 g.)
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molarity=moles/L of solvent (i.e. volume) moles=mass/molar mass molarity=(mass/molar mass)/volume 1.25 M = (60 g/(40g/mol))/V solving for V, V (in L)=(60 g/(40g/mol))/1.25M
So the answer is 1.88 L rounded?
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