The point (x0, y0) is equidistant from the line x + 2y = 0 and the point (2, 2).Find (and simplify) an equation relating x0 and y0.
this is a fun one
I'm thinking this way: first draw a sketch to see what we're dealing with: |dw:1354947273705:dw|
The pointed point is (x0,y0) agree?
Yes I would just use two distance formulas that are equal to each other
Remember @eyust707 , we don't have a fixed point on the line, so we can't directly apply the distance formula.
I'm thinking of first getting the equation of that line joining (2,2) and the line x+2y=0.
True, but to finish my thoughts, the equation of the line is y=-2x+6. Plugging in x0 and y0 into this equation should be the solution. Don't you think?
Whoa, that's a long reply @yasras :)
I believe it is (x0,y0) but I'm trying to use the formula d=Absoulte value IAx0+By0+cI/ SqrtA^2+b^2.
lol, @ allank I didnt know how to word the formula
No prob. Not sure whether that equation will work though. But simpler methods are always nice. :)
Yup, exactly, I'll try at the same time, just stuvk with how to simplify after using this formula.
You'll figure it out. Best wishes!
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