Question

Are there any inflection points for f(x)=x^2/((x^2)-4)?

Answer 1

derivate it twice and set the it equal to zero...in other words solve this equation\[f''(x)=0\]

Answer 2

I got 32+24x^2 as the numerator

Answer 3

let me check it

Answer 4

quite right :) and that results in ????

Answer 5

nothing?

Answer 6

is there any solution for\[32+24x^2=0\]???

Answer 7

I don't think so? o.O

Answer 8

it gives \[x^2=-\frac{4}{3}\] which is not a true statement for real numbers

Answer 9

So no inflection?

Answer 10

yes...no inflection point

Answer 11

hm...ok thanks :)

Answer 12

yw