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The functions f and g are differentiable and f(g(x))=x^2 for all x. If f(4)=8, g(4)=8, f'(8)=-2, what is the value of g'(4)?
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f(g(x))=x^2 f'(g(x))*g'(x)=2x f'(g(4))*g'(4)=2(4) Do you see what to do from here?
What should I do next?
g(4) = ??
I don't get it.
what is g(4)
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8.
so f'(g(4))*g'(4)=2(4) becomes f'(8)*g'(4)=2(4)
what is f'(8)
-2.
now replace f'(8) with -2 and solve for g'(4)
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So the answer is -2?
yes
Thanks for the help. Sorry I was clueless.
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