Question

(12w^4-6w^3+w^2)/(3w^2 )

Answer 1

\[{12w^4-6w^3+w^2 \over 3w^2}={12w^4 \over 3w^2}-{6w^3 \over 3w^2}+{w^2 \over 3w^2}\]Does this help you see how you can simplify it

Answer 2

\[\huge {x^a \over x^b}=x^{a-b}\]

Answer 3

oh my. algebra comes back to haunt me...
building off of @ChmE ...
simplify each term...
so you get \[4w^2 - 2w+\frac{ 1 }{ 3 }\]
if you want to you can rewrite it as...
\[\frac{ 12w^2-6w+1 }{ 3 }\] by multiplying each term by 3

Answer 4

(12w^4)/(3w^2 ) - (6w^3)/(3w^2 ) + w^2/(3w^2 )
4w^2 -
how do I divide the 6w^3/3w^2

Answer 5

I divide it leaves me with 1.5 on the exponent

Answer 6

\[\huge {x^a \over x^b}=x^{a-b}\]

Answer 7

\[\large {w^3 \over w^2}=w^{3-2}=w\]

Answer 8

in other words, you subtract the bottom exponent from the top exponent.
you don't divide the exponents.

Answer 9

okay I got it. Thanks