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Solve the given equation. (Enter your answers as a comma-separated list. Let k be any integer): 7 cos θ sin θ + 2 cos θ = 0
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I tried it and got \[\theta=\frac{ \Pi }{ 2 } and \frac{ 3\Pi }{ 2 }\] ...but its wrong
First factor out the cos theta: \[\cos(\theta)(7\sin(\theta) + 2) =0\] \[\rightarrow \cos \theta =0 \] or \[7\sin(\theta) + 2 = 0\] Jut solve those two.
yeah, that's what I did and since the second one you cant find the sine of -2/7 I can't solve for that one. Which leaves only pi/2 and 3pi/2 for the first one.
you can find sin(x) = 2/7 then use the angles in any quadrant to fin the solution sin is negative in the 3rd (pi + x) and 4th quadrant (2pi - x) this will allow you to find all the solutions.
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