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Mathematics 7 Online
OpenStudy (anonymous):

Find the value of k.

OpenStudy (anonymous):

OpenStudy (anonymous):

The value of k where?

OpenStudy (anonymous):

From the attached picture @mightyrecords

OpenStudy (anonymous):

What i have done is swapped the 3^k with the 42(3^3/2). so i got something like 3^7/2+3^5/2+3^3/2-3^k=42(3^3/2). are we okay upto that point

OpenStudy (anonymous):

maths made simpler. wish i had that application for writing answers with a stylus. pc's suck in maths!

OpenStudy (anonymous):

ktnguyen, the 42u in the first equations has power 3

OpenStudy (anonymous):

The answer is given as 4.5....

OpenStudy (anonymous):

Please help... :/

OpenStudy (dls):

I got it :)

OpenStudy (anonymous):

please show. are you still using logs and indices?

OpenStudy (dls):

\[(\sqrt(3))^7+(\sqrt(3))^5+(\sqrt(3))^3+42(\sqrt 3) \] You can solve this part I guess,you will get around 140.3 u can round it off to 140

OpenStudy (dls):

now 140 is 3 to the power what? we know 3^2=9 3^3=27 3^4=81 3^5=243 oops,so 140 lies somewhere betwen 4 and 5 so its 4.5 just a layman basic maths :)

OpenStudy (anonymous):

If you use logs from DLS's answer you will get that exact answer 4.5

OpenStudy (anonymous):

it will be something like (log 140.3)/log3=k

OpenStudy (dls):

@BelleFlower ?

OpenStudy (raden):

|dw:1354956137036:dw|

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