Question

Find the minimum y-value on the graph of y=f(x). f(x)=x^2+8x-6 the minimum y-value is y=

Answer 1

Well it's a parabola with a positive a value so the minimum y-value is at the vertex. x-coordinate of vertex=-b/2a. to find y-coordinate, plug in the x-coordinate of the vertex into the original equation.

Answer 2

can you help me with that

Answer 3

Alright. Well parabolas are in the form y=ax^2+bx+c. So in this case, a=1, b=8 and c=-6 (make sure you understand how I got these numbers).

x of vertex = -b/2a= -8/(2*1)=-8/2=-4
y of vertex = (-4)^2+8(4)-6=16+32-6=42

Answer 4

ok now how do I find the y- value

Answer 5

-_- it's in my post

Answer 6

would it be the y of vertex

Answer 7

is the y value the the yof vertex

Answer 8

In my first post: "minimum y-value is at the vertex"