let f be a function such that f''(x)=6x+12
find f(X) if the graph of f is tangent to the line 4x-y=5 at the point (0,-5)
@phi
Did you integrate it ?
no
|dw:1354983972774:dw|
should i integrate 2 times?
Yes.
First step is find f'(x) by integrating once remember to include the constant
3x^2+12x+c
2nd step is figure out the constant using the info given
-5=c
take the antiderivative of the equation f'(x) = 3x^2 + 12x + c the tangent line given is 4x - y = 5, or y = 4x - 5 so f'(x) = 4 when x = 0 use this information to solve for c 4 = 3(0) + 12(0) + c c = 4 plug in c to get f'(x) = 3x^2 +12x + 4 now take the antiderivative of this equation to get f(x) = x^3 + 6x^2 + 4x + c plug in the point (0, -5) to solve for c -5 = 0 + 0 + 0 + c c= -5 f(x) = x^3 + 6x^2 + 4x - 5
-5=c NO the first derivative is the slope. you have to match the slope of the given line
4x-y=5 ?
yes and in slope-intercept form y= 4x-5 slope is 4
okay
what to do next
3x^2 +12x +c = slope slope=4 at point (0,-5)
so c=4
yes. now you can integrate again to find f(x) remember the constant
\[x^3+6x^2+4x+C\]
now how to find c
yes but you know a point on the curve (0, -5)
c=-5
yes, see maya's post for the computation in one write-up
thanks how to find average value of f(x) on the closed interval (-1,1)
find the area under the curve f(x) the average f(x) is the height that gives the same area height*width = area under the curve so integrate between -1 and 1 and then divide by the width ( 2)
Does that make sense?
hmm but is their aother instead of graphing it
graphing? I would integrate and divide by 2
got u what we got before (f(x)) should be integrated on -1 to 1 and divide by 2
right?
yes
thx
Join our real-time social learning platform and learn together with your friends!