Question

2 cosxsinx=sinx on [0, 2pi] please find all solutions

Answer 1

lots of ways do do this problem

here is 1

2cos(x)(sin(x) - sin(x) = 0

take out the common factor

sin(x)(2cos(x) - 1) = 0

to make the equation true sin(x) = 0

and cos(x) = 1/2 (1st and 4th quadrants)

you just need to find the angles...

Answer 2

Thanks You! I was wondering if I was doing it right method wise. Thank you again :)

Answer 3

if you divide both sides by sin(x) you will miss the solution sin(x) = 0 and only have cos(x) = 1/2

Answer 4

its 0,pi, pi/3, 5pi/3 right?

Answer 5

thats it. well done