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Mathematics 21 Online
OpenStudy (anonymous):

i need help:

OpenStudy (anonymous):

with...

OpenStudy (anonymous):

\[\sqrt{4x-y}=3d\]

OpenStudy (anonymous):

solve for x

OpenStudy (anonymous):

You can square both sides, to start with.

OpenStudy (anonymous):

kk

OpenStudy (anonymous):

oh do you just need x by itself? i thought you wanted like actual values. ok phew

OpenStudy (anonymous):

lol

OpenStudy (anonymous):

getting x by itself is getting the actual values.

OpenStudy (anonymous):

no i meant like a numerical value

OpenStudy (anonymous):

it would be a numerical value. Determined by unknown d and variable y.

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

i have know idea what to do

OpenStudy (anonymous):

did you square both sides?

OpenStudy (anonymous):

ya

OpenStudy (anonymous):

what did you get

OpenStudy (anonymous):

umm idk

OpenStudy (anonymous):

what do you mean? well i got 4x-y=9d^2

OpenStudy (anonymous):

\[\sqrt{4x-y}=3d\]ummm

OpenStudy (anonymous):

i need to solve for x

OpenStudy (anonymous):

well squaring both sides would get you (squareroot 4x-y) ^2 = (3d)^2

OpenStudy (anonymous):

how do you get ^2

OpenStudy (anonymous):

and so now you're squaring a square root. it's like (squareroot of 4)^2 square root of 4 is 2 right? so it would be 2^2 which is 4 again. so basically if you're squaring a square root, you're not really doing anything so the square root and square cancel each other out if that makes sense

OpenStudy (anonymous):

oh ^2 means sqaure

OpenStudy (anonymous):

oo

OpenStudy (anonymous):

so you get how to square both sides then?

OpenStudy (anonymous):

idk this is my first time doing this or a problem like this

OpenStudy (anonymous):

oh ok well have you done questions like this: x^2 = 25

OpenStudy (anonymous):

ya

OpenStudy (anonymous):

that would be 5 ya

OpenStudy (anonymous):

yeah this question is pretty much the same thing

OpenStudy (anonymous):

oo

OpenStudy (anonymous):

so in the x^2=25 you basically square rooted both sides. so square root of x^2 = square root of 25 x=5 but it in this question you have to square both sides, give it another try

OpenStudy (anonymous):

so you square the 3d

OpenStudy (anonymous):

yup and also the sqrt 4x-y

OpenStudy (anonymous):

so would it be 9d

OpenStudy (anonymous):

9d^2 but yeah

OpenStudy (anonymous):

kk then what do i do

OpenStudy (anonymous):

did you also square the other side?

OpenStudy (anonymous):

so would it be 16x-y^2

OpenStudy (anonymous):

no because remember its squareroot of 4x-y already. so squaring it gets you squareroot of 4x-y times squareroot of 4x-y which is just 4x-y

OpenStudy (anonymous):

so it stays the same

OpenStudy (anonymous):

yeah

OpenStudy (anonymous):

can you solve it now? you just have to get x by itself

OpenStudy (anonymous):

would the square roots still be there

OpenStudy (anonymous):

no

OpenStudy (anonymous):

k

OpenStudy (anonymous):

so it would look like 4x-y=9d

OpenStudy (anonymous):

ok well you should also probably ask your teacher this too cause in math it's really important to know why things happen

OpenStudy (anonymous):

yeah exactly

OpenStudy (anonymous):

kk i dont have a teacher

OpenStudy (anonymous):

oh...how does that work?

OpenStudy (anonymous):

well my mom is my teacher but my mom is in the hospital

OpenStudy (anonymous):

ohh ok

OpenStudy (anonymous):

ya

OpenStudy (anonymous):

how do i get x by it's self

OpenStudy (anonymous):

sorry if you dont mind me asking, what grade are you in? like technically, like your age

OpenStudy (anonymous):

14 in 9

OpenStudy (anonymous):

so in an equation whatever you do to one side, you have to do to another. so you could add y to both sides which would get you 4x by itself

OpenStudy (anonymous):

sorry again, (none of my business i know) but why don't you go to school?

OpenStudy (anonymous):

so what i got was 4x=9dy drama and lot of fighting

OpenStudy (anonymous):

that's right except that it's d^2 not just d

OpenStudy (anonymous):

oh, well i'm sorry. hope it works out, whatever it is

OpenStudy (anonymous):

oo k

OpenStudy (anonymous):

thank you well we are having hard times my bf just got put in jail for a year

OpenStudy (anonymous):

aww :/ Imagine all the people, living life in peace... *swaying to the awesome music* sorry, only thing i could think of

OpenStudy (anonymous):

It's good that you're doing math and stuff though

OpenStudy (anonymous):

lol thank you hes only 15

OpenStudy (anonymous):

i thought you couldn't go to jail unless you're an adult? well i suppose different countries

OpenStudy (anonymous):

ya well i live in hawaii so there is only two jails and one prison and a whole lot of bad kids they do what they have to

OpenStudy (anonymous):

ohh the kids do what they have to?

OpenStudy (anonymous):

ya well know that i look back at what happened it is his own problem

OpenStudy (anonymous):

oh. well anyways good luck. time heals

OpenStudy (anonymous):

ya kk so know what do i do with 4x=9d^2y

OpenStudy (anonymous):

oh i thought you'd solved it. well think about, this time entire time you've been doing things to both sides. how would you get x by itself this time?

OpenStudy (anonymous):

you divide 4 on both sides

OpenStudy (anonymous):

because what happens on one side you do to the other

OpenStudy (anonymous):

yeah! exactly! :D good job

OpenStudy (anonymous):

thank you so it would be 2.25 d^2y

OpenStudy (anonymous):

wait what? so i had 4x=9d^2 + y and so x= (9d^2 + y)/4

OpenStudy (anonymous):

ya and that is what i did then i divided 9/4=2.25

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