Ask your own question, for FREE!
Algebra 12 Online
OpenStudy (anonymous):

I have a great deal of problems with these can anyone help

OpenStudy (anonymous):

f(y)=y+1/y^2-y ...The question is.....The domain of the function is???

OpenStudy (anonymous):

The domain is all the points where the function is defined. The problem here is that you might end up dividing by zero. So the function isn't defined when that happens, but is defined everywhere else.

OpenStudy (anonymous):

I am totally lost

OpenStudy (anonymous):

how?

OpenStudy (anonymous):

Are you saying that it is undefined

OpenStudy (anonymous):

The domain would be all real except for 0. It can't be 0.

OpenStudy (anonymous):

It's undefined at points where the function ends up trying to divide something by zero. Because you can't do that.

OpenStudy (anonymous):

The only value that you can't plug into y would be 0, since there is fraction with the y variable in the denominator. Every other value you can use. Like stated above, you can't divide by 0. You can divide by anything else.

OpenStudy (anonymous):

That means the domain is all real except for 0.

OpenStudy (anonymous):

Assuming by y+1/y^2-y you meant: \[\frac{y+1}{y^2} - y\] and not \[\frac{y+1}{y^2-y}\]

OpenStudy (anonymous):

In the first one you can't have any values of y that make y^2 = 0. In the second one you can't have any values of y that make y^2 - y = 0.

OpenStudy (anonymous):

oh man, tired brain. The way you wrote it, it would look like this: \[y + \frac{1}{y^2} - y = \frac{1}{y^2}\] so maybe I just implicitly assumed that you intended for there to be brackets around some of it, so that it's one of the two I wrote above...

OpenStudy (zehanz):

Sabrena: I think you meant\[f(y)=\frac{ y+1 }{ y^2-y }\]Anyway, scarydoor explained to you what the domain of a function is. Think about it this way: f(y) is a formula that does this calculation with a number (y) you put in. So f(2) = (2+1)/(2²-2)=3/2. Now you might think: I can throw in any number, and f does the same calculation every time, so why is the domain not all numbers? Well, it is, almost! You will certainly know that dividing by 0 is not a good idea. In fact, it's impossible. Now if you try to calculate f(0) or f(1), you will see that this leads to dividing by 0. So the domain is: all real numbers except 0 and 1.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!