Question

find the derivative of In(x/2)

Answer 1

Well the derivative of ln(x) is 1/x
So, that is half the battle right there. Then you must multiply by the chain rule. So you get (1/x)*(1/2)

Answer 2

u are wrong, @cherio12
y=In(x/2)
let u=x/2 ------> du/dx = 1/2
y=ln(u) ---------> dy/du = 1/u = 1/(x/2) = 2/x
dy/dx = du/dx * dy/du
dy/dx = 1/2 * 2/x = 1/x

Answer 3

thanks

Answer 4

yw

Answer 5

Yah you had the right idea with the chain rule @cherio12 :) But you just forgot to place the ENTIRE argument of the natural log into the denominator, not just the x.\[\large \large \frac{d}{dx}\ln\left(\frac{x}{2}\right)=\frac{1}{\left(\frac{x}{2}\right)}\frac{d}{dx}\frac{x}{2}\]

\[\large =\frac{2}{x}\cdot \frac{1}{2} \quad = \quad \frac{1}{x}\]