Question

find ∫√ 5x+1 dx

Answer 1

\[\int\limits \sqrt{5x+1}dx; \psi = 5x+1 \implies d \psi = 5 dx \implies \frac{1}{5}\int\limits \psi^{\frac{1}{2}}d \psi \]\[= \frac{2}{15} (5x+1)^{\frac{3}{2}}+C\]

Answer 2

the answer has these steps