Question

You have 80 yards of fencing to enclose a rectangular region.find the dimensions of the rectangle that maximize the enclose area.what is the maximize area?

Answer 1

I need all the steps!

Answer 2

a+a+b+b=80
2a+2b=80
a+b=40
a=40-b

area=A=a*b
A=(40-b)*b
A=40b-b^2
To get a maximum value, take the derivative of A with respect to b, and set it to zero.
dA/db=40-2b
0=40-2b
2b=40
b=20
a=40-b
a=40-20
a=20
20 yards by 20 yards