Question

what is the slope of 3x+5y=5 and -20+12y=0 are they perpendicular, parallel, or neither?

Answer 1

Solve each equation for y. Then you get an equation in the form y = mx + b
m, which multiplies x, is the slope. If the slopes are the same and b is different, the lines are parallel. If the slopes multiply to give you -1, the lines are perpendicular. If neither of the above, the lines are neithe perpendicular, nor parallel.

Answer 2

Start with the first equation:
3x + 5y = 5
5y = -3x + 5
y = (-3/5)x + 1
Slope is -3/5, b = 1 (where line crosses y-axis)
Now solve the second eqaution for y and post what you get.

Answer 3

they are perpendicular

Answer 4

-20x+12y=0
12y=20x+0
12/20=5/3

Answer 5

12y = 20x
divide both sides by 12,
y = (20/12)x
y = (5/3)x
Since (5/3)(-3/5) = -1, lines are perpendicular