Question

At one instant, a 17.5-kg sled is moving over a horizontal surface of snow at 3.50 m/s. After 8.75 s has elapsed, the sled stops. Use momentum approach to find the average friction force acting on the sled while it was moving

Answer 1

\[F \Delta t = m \Delta v\]. then solve for frictional force.
F = mv/ t
7N

Answer 2

note:\(\Sigma F= F_f=\frac{dP}{dT}\)

Answer 3

where \(P= m\Delta v=m(v-u)\)