Question

a sample of a radioactive substance was put in storage 6 years ago. It's half-life is 5.5 years. If 8.3 gm of the original substance remains in the sample now, what is the initial quantity of the substance (accurate to two significant figures)?

Answer 1

so your equation that you have to know and work with is...\[(\frac{1}{2})^{\frac{ 6 }{ 5.5 }} = \frac{8.3}{x}\] with x being your orignial amount

Answer 2

that fraction on top is \[\frac{6}{5.5}\] btw

Answer 3

that should help you out a lot