Find all solutions in the interval [0, 2π).

sec^2 x - 2 = tan^2 x

HELP! :o

Question

Find all solutions in the interval [0, 2π).

sec^2 x - 2 = tan^2 x 

HELP! :o

lukecrayonz · Answer

I'm pretty sure the answer is no solution..

raden · Answer

there is no solution... maybe, the typo there

anonymous · Answer

$$\sec^2 x - 2 = \tan^2 x $$$$\sec^2 x - 1 = \tan^2 x +1$$$$\sec^2x=\tan^2x+1$$$$\sec^2x-1=\sec^2x$$$$-1 \not= 0$$No Solution

lukecrayonz · Answer

okay thank you so much! can you help me with one more question? @ChmE

anonymous · Answer

sure

lukecrayonz · Answer

A high-altitude spherical weather balloon expands as it rises due to the drop in atmospheric pressure. Suppose that the radius r increases at the rate of 0.16 inches per second and that r = 38 inches at time t = 0. Determine the equation that models the volume V of the balloon at time t and find the volume when t = 280 seconds.

anonymous · Answer

btw here is a good reference site for these types of problems http://www.sosmath.com/trig/Trig5/trig5/trig5.html

anonymous · Answer

idk sry. I can't do word problems

lukecrayonz · Answer

I have another then! @ChmE

lukecrayonz · Answer

Find the inverse of 3√(x/8) -4

anonymous · Answer

$$3\sqrt{{x \over 8} -4}$$is this the question

lukecrayonz · Answer

yes! the three is the little number

lukecrayonz · Answer

@sirm3d help with the inverse question please!

sirm3d · Answer

starting with x, divide by 8, subtract by 4, take the cube root
Inverse: starting with x, cube it, add 4, then multiply by 8

sirm3d · Answer

it's like socks before shoes. the inverse: shoes before socks

sirm3d · Answer

the inverse of the function is $$\large (x^3+4)(8)$$

lukecrayonz · Answer

thank you! you're a lifesaver

sirm3d · Answer

^^