Question

what is the sum of the square roots of 16i?

Answer 1

\[i \sqrt{16}= \pm 4i\]

Answer 2

i think @casanovaxx has done it incorrectly

Answer 3

answer should be (4*\[e^{ipi/4}\])

Answer 4

and off course both +/- sign

Answer 5

Okay, the possible answers given are -8, 0, 4\[\sqrt{2}\] +4\[\sqrt{2i}\], and 8i

Answer 6

sorry that third one is , \[4\sqrt{2}+4\sqrt{2i}\]

Answer 7

8i? or the correction i added for the long one?

Answer 8

square roots of \(i\) are \(\frac{\sqrt{2}}{2}+\frac{\sqrt{2}}{2}i\) and
\(-\frac{\sqrt{2}}{2}-\frac{\sqrt{2}}{2}i\)
and get 0

Answer 9

the 16 of course is unimportant, you multiply the above numbers by 4
when you add you still get zero