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Mathematics 9 Online
OpenStudy (anonymous):

find the dot product v⋅w: for v=i-j, w=i+j

OpenStudy (richyw):

\[\mathbf{v}\cdot\mathbf{w}=\langle 1,-1\rangle\cdot\langle 1,1\rangle\]\[=1(1)+-1(1)=0\]

OpenStudy (anonymous):

do you know how i would find the angle to that?

OpenStudy (richyw):

plot those two vectors onto a graph.

OpenStudy (anonymous):

ok and find the missing angle?

OpenStudy (richyw):

you can also use is the fact that for two vectors with magnitudes \(a\) and \(b\), with angle \(\theta\) between the two vectors, the dot product is\[\mathbf{a}\cdot\mathbf{b}=ab\cos{\theta}\]

OpenStudy (richyw):

so \(0=\cos{\theta}\)

OpenStudy (anonymous):

ok thats simple

OpenStudy (anonymous):

thanks bro

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