Question

....

Answer 1

start by factorising the numerator and denominator

Answer 2

the vertical asymptotes exist where the denominator is zero...

Answer 3

ok... so you can eliminate the (x+3) and you will have a point of discontinuity at x = -3

so it simplifies to

\[y = \frac{(x -2)}{(x - 4)}\]

so a vertical asymptote exists at x = 4

there is a horizontal asymptote at y =1 found by division...

so you are basically graphing hyperbolas