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Mathematics 12 Online
OpenStudy (anonymous):

....

OpenStudy (campbell_st):

start by factorising the numerator and denominator

OpenStudy (campbell_st):

the vertical asymptotes exist where the denominator is zero...

OpenStudy (campbell_st):

ok... so you can eliminate the (x+3) and you will have a point of discontinuity at x = -3 so it simplifies to \[y = \frac{(x -2)}{(x - 4)}\] so a vertical asymptote exists at x = 4 there is a horizontal asymptote at y =1 found by division... so you are basically graphing hyperbolas |dw:1355081263952:dw|

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