Question

find the real solution
x^-2

Answer 1

\[x \neq 0\]

Answer 2

\[x ^{-2}+9x ^{-1}+18=0\]

Answer 3

that is the formula

Answer 4

set x^-1 as u which makes x^-2 to u^2 and solve as a 2n degree equation

Answer 5

Just swing the negative exponents in the denominator.

Answer 6

still confused

Answer 7

?

Answer 8

u^2+9u+18=0

And then the answer to x should be 1/x1 and 1/x2

Answer 9

i mean u1 and u2, to get the values of x1 and x2

Answer 10

since x^-1 = 1/x and x^-2 = 1/x^2

Answer 11

\[\frac{ 1 }{ x ^{2} }+\frac{ 9 }{ x }+18=0\]

Answer 12

okay so what would be the answer?