Linear Systems in Two Variables with applications. solve using elimination or substitution. 4x + 3/4y = 14 -9x+ 5/8y = -13
Do you have an idea on what would be easier to use, elimination or substitution?
not really... i know elimination mostly.
Alright, well lets go with elimination then. (For this case it appears to be the easier way to solve it)
What variable do you want to get rid of first?
\[4x+\frac{ 3y }{ 4 } = 14\] \[-9x +\frac{ 5y }{ 8 } = -13\] to make it easier, multiply each equation by the denominator \[16x+ 3y = 56 \] call this equation 1 \[-72x +5y = -104\] call this equation 2 the next few steps requires algebra. ELIMINATION multiply equation 1 by -5 and equation 2 by 3 \[-80x- 15y = -280 \] \[-216x +15y = -312\] add \[-296x = 592 \] \[x = 2 \] plug this back into either equation 1 or 2 I'll choose equation 1. \[16(2)+ 3y = 56 \] \[y=3\]
that is perfect.. thank you so much, i didn't realize i could mulitply everything by the denominator.
yeah, sometimes, you just hafta learn certain tricks to stuff. cuz you could've done it with fractions, but those are a nightmare....
Join our real-time social learning platform and learn together with your friends!