Question

\[4b^{2} + 8b = 0\]

Please show me the steps to solve

Answer 1

Factor out b would be your first step

Answer 2

b(b+8)=0

so now you can say

b=0
and
b+8=0

Answer 3

usually when factoring out, you subtract from both sides? here you just eliminate 4?

Answer 4

Wow ok got my glasses now lol.

you would factor out 4b

4b(b+2)=0

Answer 5

XD I was about to say

Answer 6

Yeah sorry about that.

so 4b=0
b=0

and b+2=0
b=-2

Answer 7

What happens to the 8? did you subtract 4 from it as well?

Answer 8

When you pull out the 4b its like dividing every term by 4b

8b/4b=2

Answer 9

I see so you would distribute divide 4b to 4b,8b and 0.

Answer 10

Can you rewrite it out again?

Answer 11

Im not sure what you're not understanding

Factor out 4b, which divides every term by 4b

4b(4b^2/4b+8b/4b)
4b(b+2)