$$4b^{2} + 8b = 0$$

Please show me the steps to solve

Question

$$4b^{2}  + 8b = 0$$

Please show me the steps to solve

anonymous · Answer

Factor out b would be your first step

anonymous · Answer

b(b+8)=0

so now you can say

b=0
and 
b+8=0

anonymous · Answer

usually when factoring out, you subtract from both sides? here you just eliminate 4?

anonymous · Answer

Wow ok got my glasses now lol. 

you would factor out 4b

4b(b+2)=0

anonymous · Answer

XD I was about to say

anonymous · Answer

Yeah sorry about that.

so 4b=0
b=0

and b+2=0
b=-2

anonymous · Answer

What happens to the 8?  did  you subtract 4 from it as well?

anonymous · Answer

When you pull out the 4b its like dividing every term by 4b

8b/4b=2

anonymous · Answer

I see so you would distribute divide 4b to 4b,8b and 0.

anonymous · Answer

Can you rewrite it out again?

anonymous · Answer

Im not sure what you're not understanding

Factor out 4b, which divides every term by 4b

4b(4b^2/4b+8b/4b)
4b(b+2)