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Chemistry 17 Online
OpenStudy (anonymous):

I really need help with this one: This is whats given: 300k 2atm 248.3 g NaCr2O7 99.6 g NH4Cl We need to find the volume of N in liters. Na2Cr2O7 + NH4Cl --> NaCl +Cr2O3 +H2O

OpenStudy (aaronq):

that equation is not right, where did the Nitrogen go?

OpenStudy (anonymous):

jeez! great I didnt add it! Its on the end haha...

OpenStudy (anonymous):

its just + N2 thanks..

OpenStudy (aaronq):

okay, so balance the equation and find how many moles you have of N2 then use PV=nRT, and solve for V

OpenStudy (anonymous):

but the part i am confused is the 248.3 g and 99.6 g which one to use?

OpenStudy (aaronq):

the first one doesn't have nitrogen, so it wouldn't contribute to the final nitrogen product, right?

OpenStudy (anonymous):

maybe just show me how…

OpenStudy (aaronq):

did you balance the equation?

OpenStudy (anonymous):

sorry, yes I did. But I stil dont understand what I should next.

OpenStudy (aaronq):

find the number of moles of reactant NH4Cl n = 99.6 g/molar mass of NH4Cl use the coefficients of the balanced reaction to find the moles you produced plug all the values they gave you into PV=nRT

OpenStudy (anonymous):

yeah i did that but what about the other one (248.3 g)?

OpenStudy (aaronq):

they just gave you that to try to confuse you

OpenStudy (anonymous):

oh okay, ahah….

OpenStudy (anonymous):

so how do I know which one to choose….

OpenStudy (anonymous):

since the other one doesn't have nitrogen in it?

OpenStudy (aaronq):

they just want you to know what you're doing. yeah, well you wouldn't use something that doesn't have what you're looking for.

OpenStudy (aaronq):

like if they asked for the amount of Chromium, you wouldn't use NH4Cl

OpenStudy (anonymous):

okay, makes sense.

OpenStudy (aaronq):

(Y)

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