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Write the expression in the form A log(x)+B log(x+1)+C log(x-2) using the laws of logarithms
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\[\large \log((x^{3}\sqrt{x+1})/(x^2-4x+4))\]
@Chlorophyll
Log ( A/ B ) = log A - Log B
i get this so far \[\large \log(x^{3})+\log(\sqrt{x+1})-\log(x^{2}-4x+4)\]
dunno if its right
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Bring the power down: 3 log x + (1/2) log ( x +1) - 2log ( x -2)
Hmm, so you factored x^2-4x+4 as (x-2)^2 and then put the 2 in front?
Yes, always attempt to convert into simplest form :)
I see, that was way simpler than i thought. Thanks
:)
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