Question

a 2 kg rubber ball moving at 6m/s to the right hits a stationary 6 kg. after the collision, the 2 kg ball has a velocity of 3m/sec in the opposite direction. find the velocity of the 6kg ball

Answer 1

momentom before and after the collision have to be equal.
so you get m1v1+m2v2 = momentum total
(2)(6)+(6)(0)=12
knowing that it has to equal 12 and knowing your new speed of the 2kg ball you get
(2)(3)+(6)(x)=12
x=(12-6)/6
x=1

Answer 2

sorry i need to make a change to that give me a min

Answer 3

my answer sheet says 3
@roblsander

Answer 4

(2)(-3)+(6)(x)=12
x=(12+6)/6
x=3

Answer 5

i forgot to include that the 2kg was moving opposite compared to before which makes it -3m/s instead of 3m/s

Answer 6

thanks @roblsander

Answer 7

No problem

Answer 8

can you help me with another problem? @roblsander

Answer 9

depends what it is ill try

Answer 10

two rubber balls collide in a collision, one ball has a mass of 2 kg and has a velocity of 6m/s due east. the other ball has a mass of 6 kg and is traveling behind the other ball at a velocity of 8 m/sec due east. after the collision, the 6 kg ball slows down to 7 m/sec . find the velocity of the 2 kg ball after the collision

Answer 11

@roblsander

Answer 12

\[P_t=m_1v_1+m_2v_2\]
\[P_b=(2)(6)+(6)(8)\]
\[P_b=60\]
\[P_b=P_a\]
\[60=(6\times7)+(2x) \]
\[x=9\]