Question

a horizontal force of 50N is needed to keep a 25kg block moving with a constant velocity of magnitude 5m/s across a horizontal table. what is the coefficient of kinetic friction?

Answer 1

do you knw the friction?

Answer 2

nvm the friction....

so the thing is...

Fapplied-Ffriction = Fnet

and Fnet = 0 because speed is constant...

so, Fapplied = 50

therefore,

u = coefficient of friction

50-uFnormal = Fnet

Fnormal is mg = 245 N

so,

Fnet = Fapplied - uFnormal

0 = 50 -u245

u245 = 50

u = 50/245

u = 0.20

so, my dear frnd, coefficient of friction is 0.20

Answer 3

thanks alot man

Answer 4

no problem :D