Question

Help me ?):

Answer 1

if f(x)= 1/x+2, what is f^-1(x)?

Answer 2

f(x)=y=1/x+2
you need to solve for x with these inverse problems which just means rearranging your equation to isolate x on one side of the equations
since y=1/x+2 your next step would be to subtract the 2
y-2=1/x
your next step would be to multiply by x
x(y-2)=1
then divide by y-2
x=1/(y-2)

Answer 3

i got \[f^-1(x)=\frac{ 1 }{ x-2 }\]

Answer 4

y should be on the bottom 1/y-2

Answer 5

@jim_thompson5910

Answer 6

@zepdrix

Answer 7

\[\large f(x)=\frac{1}{x+2}\]
\[\large g(x)=\frac{1}{x}+2\]

Which one is the correct format, f or g? :)

Answer 8

f?

Answer 9

\[\large \text{Let}\quad f(x)=y, \qquad \rightarrow \qquad y=\frac{1}{x+2}\]Taking the inverse gives us,\[\large x=\frac{1}{y+2}\]Multiply both sides by (y+2), giving us,\[\large x(y+2)=1\]Divide both sides by x,\[\large (y+2)=\frac{1}{x}\]Subtract 2 from each side,\[\large y=\frac{1}{x}-2\]Rewrite with inverse notation,\[\large f^{-1}(x)=\frac{1}{x}-2\]

Answer 10

I came up with something slightly different katie :D lemme know if those steps make sense.

Answer 11

i see thank you(: