Question

if 25.98 ml of standard 0.1180M KOH reacts with 52.50 ml CH3COOH, what is the molarity of the acid solution?

Answer 1

so they're saying that you neutralized the solution, meaning that in solution there was the same amount of moles of base and acid.

So find the moles of KOH, M=n/L of solvent
the moles will be equal to those of the acid
you know the volume, M=n/V, solve for M