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OpenStudy (anonymous):
if 25.98 ml of standard 0.1180M KOH reacts with 52.50 ml CH3COOH, what is the molarity of the acid solution?
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OpenStudy (aaronq):
so they're saying that you neutralized the solution, meaning that in solution there was the same amount of moles of base and acid. So find the moles of KOH, M=n/L of solvent the moles will be equal to those of the acid you know the volume, M=n/V, solve for M
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