Question

What is the relationship between the lines determined by these two equations?
3x + 6y = 8
y = 2x – 8

A. perpendicular
B. neither parallel nor perpendicular
C. parallel
D. they are the same line

Answer 1

put them both in y=mx+b form
so
y=2x -8 is this given one
3x+6y=8
6y=8-3x
y=(-1/2)+(4/3)

Answer 2

The second line is in y = mx + b form, with m = slope = 2.
Now write teh first equation is y = mx + b form by solving for y, and compare m, the slope.

Answer 3

Solve the first equation for y and compare it to the second equation:
3x + 6y = 8.....solve this for y.
Then compare it to the second equation.

Answer 4

I got B. Is that right?

Answer 5

no..they are perpendicular i believe

Answer 6

Are you sure?

Answer 7

They are perpendicular. That means the slope is a negative inverse.

Answer 8

So the answer is B.

Answer 9

nope

Answer 10

The slope in 3x + 6y = 8 is (-1/2)
The slope in y = 2x – 8 is (2)
These two values are perpendicular.

Answer 11

Nevermind guys. I got it. THANKS!!

Answer 12

3x + 6y = 8
6y = -3x + 8
y = (-1/2)x + 4/3
Slope1 = -1/2 and slope 2 = 2
Multiply them together: (-1/2)(2) = -1 so perpendicular lines

Answer 13

What is the slope of the line that passes through the points (3, 1) and (–2, 5)?

A. 5/4


B.-5/4


C.4/5


D.-4/5