Can someone help me finish separating this differential equation?

I have y'=(sin5x)/(siny)
dy/dx=(sin5x)/(siny)
sinydy=sin5xdx
integrate both sides
-cosy=(1/2)x^2sin5

how do I get to the final explicit form?

Question

Can someone help me finish separating this differential equation?

I have y'=(sin5x)/(siny)
dy/dx=(sin5x)/(siny)
sinydy=sin5xdx
integrate both sides 
-cosy=(1/2)x^2sin5

how do I get to the final explicit form?

anonymous · Answer

I might be missing something, but isn't

$$\int\limits_{}^{} \sin(5x) = -\cos (5x) / 5$$

anonymous · Answer

regardless... you (I believe) to get it into explicit form, solve for y.  Which means taking the arc cosine.

anonymous · Answer

okay, so my last question then, is where does C go? like, as in:
arccos(1/5cos5x)+C
or
arccos(1/5cos5x+C)