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Mathematics 13 Online
OpenStudy (anonymous):

Find the Laplace transform of f(t) = 3t^(5/2) + 4t^3.

OpenStudy (anonymous):

so i get 4*3!/(s^4) but then i dont know how to figure out the first part hah

OpenStudy (abb0t):

I think you just leave the 5/2! as is?

OpenStudy (anonymous):

for the first part I get [3(5/2!)]/s^(3.5)

OpenStudy (anonymous):

so then it would be 3(5/2)!/s^(7/2) ?

OpenStudy (anonymous):

yup

OpenStudy (anonymous):

alright i think im just confusing myself because the answer in the back of the book is more complex haha

OpenStudy (anonymous):

Well, you can't techncally take factorial of fraction lol! I'd leave it like that :D

OpenStudy (abb0t):

Try taking the integral from 0<t<∞

OpenStudy (anonymous):

yeah i mean wolfram knows how but im clueless ha, the integral? hmm

OpenStudy (anonymous):

maybe i can take the integral to simplify it and then go from there

OpenStudy (anonymous):

So your problem is the (5/2)! not the laplace transform lol!

OpenStudy (abb0t):

sorry i mean the gamma. isn't it the gamma that means to take the integral? i'm trying to remember. haha

OpenStudy (anonymous):

yeah so its supposed to be 45pi - 192s^(3/2)/(8s^(7/2))

OpenStudy (abb0t):

The gamma function is defined as: \[\Gamma = \int\limits_{0}^{∞}e^{-x}x ^{t-1}dx\]

OpenStudy (anonymous):

alright thanks :)

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