Find the Laplace transform of f(t) = 3t^(5/2) + 4t^3.
so i get 4*3!/(s^4) but then i dont know how to figure out the first part hah
I think you just leave the 5/2! as is?
for the first part I get [3(5/2!)]/s^(3.5)
so then it would be 3(5/2)!/s^(7/2) ?
yup
alright i think im just confusing myself because the answer in the back of the book is more complex haha
Well, you can't techncally take factorial of fraction lol! I'd leave it like that :D
Try taking the integral from 0<t<∞
yeah i mean wolfram knows how but im clueless ha, the integral? hmm
maybe i can take the integral to simplify it and then go from there
So your problem is the (5/2)! not the laplace transform lol!
sorry i mean the gamma. isn't it the gamma that means to take the integral? i'm trying to remember. haha
yeah so its supposed to be 45pi - 192s^(3/2)/(8s^(7/2))
The gamma function is defined as: \[\Gamma = \int\limits_{0}^{∞}e^{-x}x ^{t-1}dx\]
alright thanks :)
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