in the figure below mass of A=mass of B=1kg
E=10 N/C, k(spring constant)=18 N/m
block A is neutral while the block B has -1C charge size of A and B are negligible. block B is released from rest at 1.8m away from A . Initially spring is neither stretched nor compressed. find amplitude of oscillation of combined mass

Question

anonymous · Answer

CBSE me shayad ye portion nahi hai ...

anonymous · Answer

oops maf karna

anonymous · Answer

from B to A:
$\frac{1}{2} mv^2 = \int_0^{1.8} \frac{kQ_1Q_2}{r^2} dr$
then during collision, charges are transferred and B repels. use the mechanical energy conservation.

anonymous · Answer

iam sorry but would you be kind enough to solve it.............complete

anonymous · Answer

we need to find the amplitude of oscillation of combined mass

anonymous · Answer

ah. $\Sigma F= -kx=-m \omega^2 x$, sub them all in. and solve for $\omega$ note that m=A+B

anonymous · Answer

what is omea 'w'

anonymous · Answer

the angular velocity. though..wait...isn't the amplitude 1.8?

anonymous · Answer

no the amplitude is $${\frac{ \sqrt{106 }}{ 9 }}$$

anonymous · Answer

anyways i got it how to solve./