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OpenStudy (anonymous):
\[\int\limits_{0}^{\pi} (5e^x+3sinx)dx\]
OpenStudy (anonymous):
I got
....+(3sinx^2/2) but im stuck
OpenStudy (anonymous):
integrating sin doesn't give you sin^2
OpenStudy (anonymous):
The rule you tried to apply there works only for polynomials. You want to a function whose derivative is 3 sin x. And another function whose derivative is 5 e^x.
OpenStudy (anonymous):
3cosx?
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OpenStudy (anonymous):
then what do i do for this one..?
OpenStudy (anonymous):
-3 cos x
OpenStudy (anonymous):
d/dx cos x = - sin x.
OpenStudy (anonymous):
yeah i forgot the negative.. sorry
OpenStudy (anonymous):
d/dx e^x = e^x.
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OpenStudy (anonymous):
e^x is special in that regard. It's the only function with that property.
OpenStudy (anonymous):
so it stays the same... (5e^(x)-3cosx and the i just do F(b)-F(a)
OpenStudy (anonymous):
Yep. That's the fundamental theorem of calculus.
OpenStudy (anonymous):
Since you've got a pi as one boundary of the interval you're integrating over, you might end up with some things that you'll have to either leave as a symbol, like e^pi, or you'll get a decimal approximation because it'll be irrational.
OpenStudy (anonymous):
yeah i got... -116.7034632
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OpenStudy (anonymous):
Yeah. You should get a definite rational number for -3 cos pi. But Then I would leave e^pi in its symbolic form, probably... up to you.