Find the t required for a $1200 investment to double at interest rate r, compound continuously.
what was wrong with the same question you posted in the general math section?
tmi doubling time has nothing to do with the initial investment i invest $50 and @amistre64 invests $700,000 mine double to $100 and his doubles to $1,400,000 in the same amount of time it rains on the just and the unjust
indeed. and we will need to recall the formula for continuous compounding interest rates
just unsure how to solve for t
you need to know the formula for continuous compounded interest. Then solving for t will be rather simple
A=Pe^rt from what I know, but not that simple to me really...
lets redefine A, we want it to be 2P right?
yes
... fixing a few typos A=Pe^rt now lets start peeling away the layers to get to "t" 2P = Pe^rt ; divide each side by P 2 = e^rt ; ln undoes an e ln(2) = rt now it just a matter of removing the r ....
well r is given as 0.062
I'm sorry for not stating so from the start, slipped my mind
can you solve: ln(2) = rt , for t?
divide both sides by r?
correct soo ln(2)/r = t use a calculator and plug in the value for r to determine t
11.17
and note that when @amistre64 writes 2P = Pe^rt ; divide each side by P 2 = e^rt ; it means that the initial amount is a red herring. doubling time is doubling time
oh I see. Thank you so much
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