Question

how is log[x+ {(1+x^2)^1/2}] an odd function?

Answer 1

seems unlikely to me

Answer 2

for example \(f(1)=1+\sqrt{2}\) and \(f(-1)=-1+\sqrt{2}\) so it is not odd

Answer 3

i am sorry. just corrected the question.

Answer 4

ok now it is odd

Answer 5

@satellite73 how? i put -x in place of x? log[-x+ {(1+x^2)^1/2}]. thats what i get.

Answer 6

[-x+ {(1+x^2)^1/2}]*[x+ {(1+x^2)^1/2}]=1
hope it is enough hint

Answer 7

yeah i did that too and it didn't help
maybe multiply rationalize the numerator inside the log

Answer 8

hey mann this is done

Answer 9

i like @RajshikharGupta solution more than mine

Answer 10

thank u

Answer 11

thank you!

Answer 12

2*thank u