Question

factor x^3+5x^2-49x-245

Answer 1

f(x) = x^3+5x^2-49x-245
f(-5) = (-5)^3+5(-5)^2-49(-5)-245 = 0
So, x+5 is one of the factors.
Use long division/synthetic division to find the other factors.

Answer 2

Ex: f(x)=x³-5x²+49x-245
Make it equal to zero and Group factor
x^3 - 5x^2 + 49x - 245 = 0
(x^3 + 49x) - (5x^2 + 245) = 0
x(x^2 + 49) - 5(x^2 + 49) = 0
Factor out (x^2+49) leaving
(x^2 + 49)(x - 5) = 0
x^2 = -49
x =
x = +7i
x = -7i
and
x = 5 is the only real root

Answer 3

thank you!

Answer 4

that's an example

Answer 5

:) nice change up there

Answer 6

me? thnx