Question

Solve: 1+(3/x-4)=12/(x(x-4))

Answer 1

[3/(x-4)]-[12/x(x-4)]=-1
(3x-12)/x(x-4)=-1
3x-12=-x(x-4)
3x+x^2-4x-12=0
x^2-x-12=0
then or
\[x=(-b-\sqrt{ b^2-4ac})/2a\]
\[x=(1-\sqrt{1-4(1)(-12)})/2a\]
\[x=(1-\sqrt{ 1+48}/2\]
\[x=1/2-7/2\]
or
\[x=(-b+\sqrt{ b^2-4ac})/2a\
\[x=1/2+7/2\]